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  1. Question #60376 - Socratic

    It looks like a serial dilution is in order. How about this? Step 1: Dissolve 40 mg of "Lis" in 100 mL of water. " [Lis]" = (40 × 10^"-3" color (white) (l)"g")/"0.100 L" = "0.40 g/L" Step 2: Dilute 1 mL of this …

  2. Question #14c76 - Socratic

    It's worth knowing that the dilution factor, DF, tells you the ratio that exists between the volume of the diluted solution and the volume of the stock solution. DF = V diluted V stock In your case, the volume …

  3. Question #11820 - Socratic

    Here's my take on this. Assuming that the question is not incomplete, your goal here is to figure out the dilution factor, "DF", for the second dilution, and the overall dilution factor for the two dilutions. For …

  4. How do I make a #1:6# dilution of #"water"# to ... - Socratic

    Well this one is easy; of course there is a catch..... When you work with concentrated acids, you ALWAYS add acid to water and never the reverse. This is non-negotiable and it is absolutely …

  5. Aliquot is 15 ml and i made volume makeup upto 50ml.what ... - Socratic

    Aliquot is 15 ml and i made volume makeup upto 50ml.what will be its dilution factor?

  6. Question #f9956 + Example - Socratic

    Here's how you can do that. A solution's concentration in parts per million, or ppm, tells you the number of grams of solute you get for every 10^6 = 1,000,000 grams of solution. Similarly, a solution's …

  7. Question #682c7 - Socratic

    Here's how you could do that. For starters, you can only dilute the original solution by adding water, the solvent. In any dilution, the amount of solute remains constant. So, your starting solution is 83%"v/v", …

  8. Question #a5122 + Example - Socratic

    Multiply the number that you got in the previous step by the inverse of the number on your dilution tube. For example, if the plate you selected was the #10^-2# plate, you would multiply 10 by #10^2# to get …

  9. Question #f1496 - Socratic

    Explanation: #R_1" and "R_2" are connected as serial"# #R_6=R_1+R_2" ; "R_6=1+4=5" "Omega# #R_4" and "R_5" are connected serial"# #R_7=R_4+R_5" ; "R_7=2+3=5 " "Omega# #R_6" , "R_3" , …

  10. Question #470a1 - Socratic

    You get the new concentration from a standard dilution calculation. c1V 1 = c2V 2 c2 = c1 × V 1 V 2 = 0.35 mg/mL× 15.0µL 30.0µL = 0.175 mg/mL Step 3. Calculate the mass of protein loaded on the gel …